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Help with consecutive integers asap please?
This is for a project, and I kinda need help on how to work out a solution for each of these :)
1.) Find three consecutive integers whose sum is 210. (answers are 69, 70 and 71)
2.) Find 3 consecutive odd integers whose sum is 69. (answers are 21, 23 and 25)
3.) Find 3 consecutive even integers whose sum is 60. (answers are 18, 20 and 22)
all helpful answers are appreciated :)
@bringemhome yes, I've already done that. It's just that I don't know how to work out a solution for it, like how to get the value of the variable (N in your example)
4 Answers
- Anonymous9 years ago
1. Let the numbers be: (n - 1), n and (n + 1):
(n - 1) + n + (n + 1) = 210
3n = 210
n = 70
Numbers are: 69, 70, 71
2. Let the numbers be: (n - 2), n, (n + 2)
(n - 2) + n + (n + 2) = 69
3n = 69
n = 23
Numbers are: 21, 23, 25
3. Let the numbers be: (n - 2), n, (n + 2)
(n - 2) + n + (n + 2) = 60
3n = 60
n = 20
Numbers are: 18, 20, 22
- 9 years ago
take the three as (x-1),x,(x+1).. then sum is 3x=210 =>x=70
before num is 69 and thrd num is 71
2x-1,2x+1,2x+3.. sum is 6x+3 =69=> x=11
so numbers are 21,23,25
for even numbers
2x-2,2x,2x+2.. sum is 6x=60=> x=10
numbers are 18,20,22
- Anonymous9 years ago
Hint: In each problem let n = smallest integer. Then in 1) the three integers are n, n+1, n+2
- 9 years ago
Divide the number by 3. What you get is the middle number of the series. Pick the two consecutives on each side of it.
