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Can you help me with this basic physics question?
Suppose a rocket ship moves with constant acceleration equal to 9.8m/s^2, which gives the illusion of normal gravity during the flight.
Starting from rest, what is the total distance traveled once the rocket reaches 18% the speed of light? (3.0x10^8m/s)
I know I have to find the time it takes to reach the speed first, but once I use it to find the distance, I get wrong answers.
1 Answer
- ?Lv 59 years agoFavorite Answer
Time it takes to reach 18% speed of light:
v(t) = v0 + at
(0.18)*(3.0*10^8) = 0 + 9.8t
t = (0.18)*(3.0*10^8)/9.8
Distance traveled during that amount of time:
x(t) = x0 + v0*t + (1/2)a*t^2
x((0.18)*(3.0*10^8)/9.8) = 0 + 0 + (1/2)(9.8)*((0.18)*(3.0*10^8)/9.8)^2 = 1.49*10^14 m (approximate)
Hope this helps!
