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Find the smallest whole number that when divided by?
(a) 4 gives a remainder of 3
(b) 3 gives a remainder of 2
(c) 2 gives yiu a remainder of 1
3 Answers
- 9 years agoFavorite Answer
Answer is 11.
Solved by Trail and error Method. Mathematically cannot be solved as there are 3 equations and 4 Variables.
Divider * quotient +Reminder = Dividend.
Lets call dividend as X
a) Divider is 4 and reminder is 3 .
Lets call quotient as a
equation 1:
4*a+3=X------------------------------------>1
a=(X-3)/4
b)Divider is 3 and reminder is 2.Quotient is 1
Lets call quotient as b
equation 2:
3*b+2=X----------------------------------->2
b=(x-2)/3------------------------------------>2.1
c)Divider is 2 and reminder ::1 quotient is 1
Lets call quotient as c
equation 3:
2*c+1=X------------------------------------->3
- 9 years ago
the way I looked at this was one number that meets all three objective
and so for me the number is 11