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? asked in Science & MathematicsMathematics · 9 years ago

Find the smallest whole number that when divided by?

(a) 4 gives a remainder of 3

(b) 3 gives a remainder of 2

(c) 2 gives yiu a remainder of 1

3 Answers

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  • 9 years ago
    Favorite Answer

    Answer is 11.

    Solved by Trail and error Method. Mathematically cannot be solved as there are 3 equations and 4 Variables.

    Divider * quotient +Reminder = Dividend.

    Lets call dividend as X

    a) Divider is 4 and reminder is 3 .

    Lets call quotient as a

    equation 1:

    4*a+3=X------------------------------------>1

    a=(X-3)/4

    b)Divider is 3 and reminder is 2.Quotient is 1

    Lets call quotient as b

    equation 2:

    3*b+2=X----------------------------------->2

    b=(x-2)/3------------------------------------>2.1

    c)Divider is 2 and reminder ::1 quotient is 1

    Lets call quotient as c

    equation 3:

    2*c+1=X------------------------------------->3

  • 9 years ago

    a) 7

    b) 5

    c) 3

  • 9 years ago

    the way I looked at this was one number that meets all three objective

    and so for me the number is 11

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