Can you help me work out the nth term formula for these quadratic sequences?

1,4,9,16,25,... this sequence is n^2 look to the differences

4-1 = 3

9-4 = 5

16-9 = 7

25-16 = 9 ... it is the same as your first sequence

24 should be 34

13-10=3

18-13=5

25-18 = 7

34 - 25 = 9

45 - 34 = 11

so 10-1 = 9 so ur sequence is

n^2+9

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second sequence same as the first

but begins with 6-1 = 5 , like 9 -4

what makes 9 , 6 sub 3

so it is n^2 -3 this sequence -2,1,6,13

want to ignore the first term being with n+1 instead of n

(n + 1)^2 - 3

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make sure you write the last one correctly

10,13,18,25,34