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Statistics question: Suppose you recevied a shipment of 13 televisions. Two of the TVs are defective.?
If two tvs are randomly selected, compute the probability that both tvs will work. what is the probability that at least one of the two tvs will not work? can someone break this question down so i can learn to do it for the exam? thanks
2 Answers
- M3Lv 79 years agoFavorite Answer
P[both work] = 11/13 *10/12 = 55/78, ≈ 70.5% <------
P[at least 1 doesn't work] = 1 - 55/78 = 23/78, ≈ 29.5% <-----
- erdenLv 44 years ago
long clarification W = works N = does no longer artwork WW = (5/9)(4/8) = 20/seventy two WN = (5/9)(4/8) = 20/seventy two NW = (4/9)(5/8) = 20/seventy two NN = (4/9)(3/8) = 12/seventy two a minimum of one does no longer artwork skill a million or 2 do no longer artwork P(WN or NW or NN) = (20 + 20 + 12) / seventy two = fifty two/seventy two = 13/18 short clarification a million - P(WW) a million - 20/seventy two (seventy two - 20) / seventy two fifty two/seventy two 13/18
