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transforming curves of functions problem?
Find the coordinates of the points where the graph of y=f(x+2) crosses the axes.
y=f(x) where f(x)=x(x-2)^2
i don't understand this.. please help, thanks!
2 Answers
- Anonymous9 years agoFavorite Answer
y = f(x + 2)
y = f(x)
f(x) = x(x - 2)^2
f(x) = x(x-2)^2
f(x + 2) = (x + 2)[(x + 2) - 2]^2 <------- substitute x = x + 2
f(x +2) = x^2(x + 2)
y = x^2(x + 2)
when y = 0,
0 = x^2(x + 2)
x + 2 = 0
x = -2 <--------- answer for x
when x = 0,
y = 0^2(0 + 2)
y = 0(2)
y = 0 <-------------answer for y
coordinate of interception (-2,0)
- icemanLv 79 years ago
f(x + 2) = (x + 2)(x + 2 - 2)^2
= x^2(x + 2)
the x-intercepts are: (0 , 0) & (-2 , 0)