Algebra: Work Problems. Please help meee?

Question

1.) In a factory, the ratio of  the number of male to female workers is 2:3. If 100 new female workers are hired, the number of female workers will increase to 65% of the total number of workers. Find the original number of workers in the factory.

2.) A job could be finished in 150 days if 50 men are working full time. 60 men started working on the job and after 20 days, 20 more men are added. But after 80 days, 50 men quit the job. How long could it take for them to finish the job?

M3 · Accepted Answer

q1
f for females, t for total
f = 0.6 t
f+100 = 0.65t
100 = 0.05t
t = 2000
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q2
150*50 = 7500 man-days needed
phase1: 60*20 = 1200 man-days
2nd phase: 80*60 = 4800 man-days
work remaining = 7500 - (1200+4800) = 1500 man-days
men remaining = 30
days needed = 1500/30 
= 50 more days or 130 days total
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sv · Answer

1. 100 + 2T/5 = 65T/100 Giving T = 400 whence F = 160 and M = 240 ANSWER
2. W = 150*50 mandays = 7500 mandays
    Done = 60*20 + 80*60 manday = 6000 mandays
    Now 1500 mandays needed by 30 men so 50 days more required ANSWER

Jeff Aaron · Answer

1.
m/f = 2/3
m/(f+100) = 65/100
Therefore:
2f = 3m
f = 3m/2
f = 1.5m
65(f + 100) = 100m
65(1.5m + 100) = 100m
97.5m + 6500 = 100m
100m - 97.5m = 6500
2.5m = 6500
m = 6500 / 2.5
m = 2600
f = 1.5*2600
f = 3900

? · Answer

hmmmh.. no longer positive my calculation ..enable me attempt 1st.. (sq. root of) 5 - (sq. root of) 3 ------------------------------... 2 utilising calculator, (5) ½ = 2.23 and (3) ½ =a million.seventy 3 so, (5) ½ - (3) ½ = (2.23 - a million.seventy 3) ÷ 2 = 0.5 ÷ 2 = 0.25 (i wager!)

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Algebra: Work Problems. Please help meee?

4 Answers