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pink9364
Lv 5
pink9364 asked in Science & MathematicsPhysics · 9 years ago

how do you find the theoretical ymas from firing a rocket?

my daughter is doing a physics report 12th grade, and she has to find the ymax from 20 different rocket launches she did.

Update:

find the theoretical y max from the toatal times that you collected on the football field. she shot off 20 rockets. and recorded angle, power level and time,meter lines, extra meters and total meters

Update 2:

we can talk about this on yahoo messenger if you'd like pink9364

Update 3:

recorded angle 45 on low power. time is 2.96 seconds

Meter lines 46 extra meters ,75 total meters 46.75 this is the first one out of 20

can you help ?

Update 4:

low power was the rocket was set on low.

Update 5:

it took 2.96 seconds to hit the ground and went a total of 46.75 meters

Update 6:

i don't know... this is all the teacher gave her. I am not sure why he has theoretical y max. meter lines are what are on the football field, they did this on the football field.. so when the rocket landed after the 46 meter line they figured out the number of meters after that which in this first case was .75. allot of nonsense work for one number. SO... when she fired the first rocket on its lowest power on a 45 degree angle it took 2.96 seconds to go 46.75 meters. so we have to find the height (y max) it hit before coming down to ground.

Update 7:

listen smartass. this is the student who needs help. yes i mean the y-max. you know when the rocket is launched and it gets to the max and falls. the point of when it stops and falls cos of gravity is the y-max im talking about.

THEN, the meter lines. think of a foot-ball field. you know, 10 meter, 20 meter, 30 meter marks. if you dont go back to school. the extra meter are lets say you launch the rocket and it lands on the 40 meter mark but 34cm after it. thats the extra meters. just think of a ruler. 46ft long, and 75 cm.

all i'm asking is what he means about theoretical ymax. you dont need all the other infomation.

1 Answer

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  • ?
    Lv 6
    9 years ago
    Favorite Answer

    The “y” direction generally refers to the vertical direction and the “x” direction, the horizontal. Therefore, “y(max)” would most likely refers to the maximum altitude the rocket reached.

    If the rocket took it took 2.96 seconds to hit the ground and went a total of 46.75 meters (horizontally), it is possible to determine the altitude of your rocket. You only need the time.

    To determine the rocket’s altitude, use this formula:

    h = ½gt² ….. h = height; t = time; g = gravity = 9.8 m/s²

    h = ½ x 9.8 x (2.96 / 2)

    h = ½ x 9.8 x (1.48)

    h = 7.3 m

    Notes:

    1. For these type of problems, for simplification, your allowed to ignore the effect of wind resistance.

    2. I’ve performed a calculation based on one result. If the rocket was launched many times, you could repeat the calculations for each flight (too time consuming) or most likely average you flight times and range distance.

    3. Using both the time and range data, it is easy to determine the velocity of the rocket.

    Hope this helps.

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