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Math Question Algebra 2?
I am trying to solve the following from my textbook: How much of an 8% saline solution should be added to 600ml of a 3% solution to produce a 5% solution.
Please explain your steps and how you came up with your question. The possible answers assuming the book has the correct answer. ( it is multiple choice) are 200ml,300ml,400ml, 500ml.
When I tried this twice I got 600 ml
Please explain your steps and how you came up with your question. The possible answers assuming the book has the correct answer. ( it is multiple choice) are 200ml,300ml,400ml, 500ml.
When I tried this twice I got 600 ml
1 Answer
- ranjankarLv 79 years agoFavorite Answer
LET THE QUANTITY OF 8% SOLUTION MIXED BE X ml
0.08X + 0.03*600 = ( X+600)*0.05
0.08X + 18 = 0.05X + 30
0.03X = 12
X = 12 /0.03 = 400 ML answer
check
600 X 0.03 = 18
400 X 0.08 = 32
ADD = 50
50 /1000 X 100 = 5%