Trying to compile a java code and it is giving me a weird error... all the code seems right any ideas?

"Literal Strings" are interpreted internally regarding some special characters. The newline \n character is one. But the backslash \ is another. It means to treat the following character specially or literally (the opposite of its normal treatment).

That means that inside "a quoted string" every backslash must be preceded by another backslash in order to be taken a a literal backslash.

So, in your kitty's case, double each backslash to get one backslash.

System.out.println (" /\\_/\\ ----- ");

System.out.println ("( ' ' ) / Hello \\ ");

System.out.println ("( - ) < Junior |");

System.out.println (" | | | \\ Coder!/ ");

System.out.println ("(__|__) ----- ");

Added: The sequence backslash+something is sometimes called an "escape character", because you are escaping the normal bounds of what the 'something' character means.

First answer is correct.

The

\

character 'escapes' what comes after. If you want to print that character you have to 'escape' it by

\\

that will print the \ char.

Eg change

System.out.println(" | | | \ Coder!/ ");

to

System.out.println(" | | | \\ Coder!/ ");

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