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can you help me with factoring for algebra 2?
it is factoring for the polynomial the question is 2d^3 - 5d^2 - 18d + 45
2 Answers
- ajedrezLv 78 years agoFavorite Answer
Factor by grouping.
2d(d^2 - 9) - 5(d^2 - 9)
(2d - 5)(d^2 - 9)
(2d - 5)(d + 3)(d - 3)
I hope this information was very helpful.
- oldmanLv 58 years ago
You can use what is called synthetic division
2d^3 - 5d^2 - 18d + 45=====> select a number that will divide into 45 two will not go but three will
3_| 2d^3 - 5d^2 - 18d + 45=> drop down the 2 multiply it by 3 ( we are working with only the coefficients)
-----2--------6----------------------------( add the -5 to the 6 get 1, multiply the 1 by the 3)
-----2--------1-------3--------------------(add the 3 to the -18 get -15, multiply the -15 by the 3)
-----2---------1-------3------45-------( add +45 to -45 to get 0) since we have a zero then 3 is a factor
(d-3) ( 2d² +d-15) this expand to get 2d^3 - 5d^2 - 18d + 45
