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Help with Calculus homework?

d/dx cos^2(x^3) =

a. 6x^2cos(x^3)

b. 6x^2cos(x^3)

c. sin^2(x^3)

d. -6x^2sin(x^3)cos(x^3)

e. -2sin(x^3)cos(x^3)

Please and thanks xP

4 Answers

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  • Favorite Answer

    d/dx cos(x^3)^2 =>

    2 * cos(x^3) * d/dx cos(x^3) =>

    2 * cos(x^3) * (-sin(x^3)) * d/dx x^3 =>

    -2 * sin(x^3) * cos(x^3) * 3x^2 =>

    -6 * x^2 * sin(x^3) * cos(x^3)

  • 8 years ago

    (cos(x^3))^2

    Then Simplify... I think :/

    Source(s): eh
  • 8 years ago

    diff(cos(x^3)^2, x) = - 6*cos(x^3)*sin(x^3)*x^2, d

    Source(s): Maple 16
  • Anonymous
    8 years ago

    hint: Chain rule

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