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Average acceleration problem?
an object is moving along the x axis with a velocity of 20 m/s. in 3.0 seconds, its velocity increases to 58 m/s. what is the average acceleration? if the velocity then decreases to 12 m/s in 8.0 seconds, what is the average acceleration?
1 Answer
- IanLv 68 years agoFavorite Answer
Over a chosen time interval, final velocity is equal to initial velocity, plus the change in velocity (acceleration) multiplied by time
Vf = Vi + a*t
58m/s = 20m/s + a(3.0s)
38m/s = a(3.0s)
12.7m/s^2 = a = the acceleration experienced going 20m/s -->58m/s in 3.0s
For the second part we can change what we're using as 'inital' and 'final' velocities, since this is a different time interval we're now considering. 58m/s will now be the initial velocity, and 12m/s will be the final velocity, while 8s will be the time interval.
Vf = Vi + a*t
12m/s = 58m/s + a(8.0s)
- 46m/s = a(8.0s)
- 5.75m/s^2 = a = acceleration experienced going 58m/s --> 12m/s in 8.0s