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How do I solve this algebraic system of equations with a fraction involved?
I really despise fractions and I am having a hard time solving this system of equation:
x+3y=6
1/3x+7=2
What can I do to solve this properly?
1 Answer
- MattLv 78 years agoFavorite Answer
You can start by multiplying the second equation by 3. That will get rid of the fraction. Then you'll be able to solve that equation for x:
(1/3)x + 7 = 2
x + 21 = 6
x = -15
Substituting that into the first equation, we get:
x + 3y = 6
-15 + 3y = 6
3y = 21
y = 7
So, the solution is x = -15, y = 7. Hope that helps! :)
