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Can the value of the following be found?

1^(1/1) + 2^(1/2) + 3^(1/3) + 4^(1/4) + .......

5 Answers

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  • ?
    Lv 7
    8 years ago
    Favorite Answer

    1^(1/1) + 2^(1/2) + 3^(1/3) + 4^(1/4) + .......

    Sum does not converge.

    By the limit test, the series diverges.

    Partial sum values:

    (1, 1.)

    (2, 2.41421)

    (3, 3.85646)

    (4, 5.27068)

    (5, 6.65041)

    (6, 7.99841)

  • 8 years ago

    The limit of x^(1/x) = 1, so the sum would go to infinity. A more interesting problem to ask would have been whether 1^(1/1) - 2^(1/2) + ... + n^(1/n) + (n+1)^(1/(n+1)) had a solution.

  • Anonymous
    8 years ago

    As an infinite series, the sum is +∞, as none of the terms is < 1.

  • 8 years ago

    i do not know

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  • 8 years ago

    BODMAS.

    Go for it.

    + what??

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