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To what temperature will a 50.0 g piece of glass raise if it absorbs 5275 joules of heat and its specific heat?
1. To what temperature will a 50.0 g piece of glass raise if it absorbs 5275 joules of heat and its specific heat capacity is 0.50 J/g°C? The initial temperature of the glass is 20.0°C. please help me understand this.
2 Answers
- az_lenderLv 78 years agoFavorite Answer
Q = m c delta-T
Q = 5275 J
m = 50.0 g
c = 0.50 J/(gC)
5275 J = (50.0 g) (0.50 J/gC) [ delta-T ]
211 degrees C = delta-T
So the final temperature is 20C + 211C = 231C
- 5 years ago
Let the unique warmth of glass be C J kg^-1.Okay^-1. Let the temperature reached via glass be T ok after gaining 5275 J heat. 5275 = zero.05 x C x (T-293) or T = 293 + (5275/zero.05)/C or temperature, t in deg C will take delivery of by t = 20 +(105.5x10^three)/C maximum worth of C will also be one thousand. So the temperature would upward push to at least 127 .5 degree Celsius
