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Write an equation in slope-intercept form for the line that is parallel to the given line?
and that passes through the given point.
y=3x-7; (0,4)
4y=x: (4,0)
y=2x+3: (1,7)
5y-2y=10: (3, -5)
2x+3y=7: (4,5)
y= 1/2x-1; (0,-4)
3x+4y=8: (4,-3)
now the same, but instead of parellel, find the line that is perpendicular.
y=x-6; (-1,2)
y=5-3x; (2,-4)
4x-2y=-6; (3,-2)
y=x-5; (0,5)
show your work. thank you!
1 Answer
- The GnosticLv 78 years agoFavorite Answer
y = 3x + 4
y = x/4 - 1
y = 2x + 5
Do you mean 5x-2y=10?
y = (5/2)x - 25/2
y = -(2/3)x + 23/3
y = (1/2)x + 4
y = -(3/4)x
-------
y = -x + 1
y = (1/3)x - 14/3
y = (1/2)x - 7/2
y = -x + 5
