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Abby
Lv 4
Abby asked in Science & MathematicsMathematics · 8 years ago

Help with logarithmic functions?

I'm stuck on what to do for these problems

Simplify

5^log₅x

log₂2^x

2 Answers

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  • Dr. Zorro
    Lv 7
    8 years ago
    Favorite Answer

    log_5 (x) is the the number that, when raising 5 to it, gives x.

    So by definition

    5^log_5(x) = x

    Log_2(2^x) is the number that you have to raise 2 to, to get 2^x..... So again, by definition, it is x.

  • Glipp
    Lv 7
    8 years ago

    5^log₅x = x

    log₂2^x = x log₂2 = x

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