Any help with this Physics problem?

I was going to let this one go until I saw that "Top Contributor" answer which is obviously wrong. It only proves that you don't have to give right answers to be a top contributor, you only have to answer a lot of questions. Figure the two top resistors as in parallel and the two bottom resistors as in parallel, then add them as two resistances in series and use the voltage to get the total current flowing through the circuit. Well, it's a start. But you have two voltage dividers in parallel tapped at different potentials so there's obviously a current flowing through A since one's being tapped at 4.5 volts and the other's being tapped at 6 3/4 volts. You can't do that without having a current flow between them.

The top resistance is 1/Rt=1/6+1/2, making that parallel pair 1.5 ohms. The bottom pair resistance is 1 ohm. Add them in series for 2.5 ohms and the current from the 9 volt battery is 3.6 amps total. Well, it's a start. What you have to track is the current. I'll get back to you if I last that long. Hey, it's been decades.

Sorry, I'm stuck. It's an interesting problem but all I can tell you is that the other guy is wrong. I'm not getting any of the four answers offered so I know I'm doing something wrong, too. If I get it, I'll get back.

Potential difference across the end points of A is zero and hence the current is zero.

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