math people: for this problem...........?

You could actually add 2x or subtract 4x first as it wouldn't really make a difference.

To solve the equation:

2x-2 = 4x+8

------ -------

Add 2 to both sides!

2x = 4x+10

---- --------

Subtract 4x from both sides!

-2x = 10

---- ----

Divide by -2 from both sides!

The final answer would be: x = -5

There you go!^^

Just to make sure, plug in -5 as the x-value in order to check yourself. If both sides equal the other, then the answer is correct!

STUDY HARD!(:

Try it:

add 2x to both sides:

2x - 2 + 2x = 4x + 8 + 2x

--> collect like terms, now you have

4x - 2 = 6x + 8 <-- you haven't gotten anywhere...

...try subtracting 4x from both sides

2x - 2 - 4x = 4x + 8 - 4x

--> now the 4x's cancel on the right, leaving

-2x - 2 = 8

--> now just solve for x...add 2 to both sides:

-2x - 2 + 2 = 8 + 2

--> -2 + 2 = 0...-2x + 0 = -2x

-2x = 10

--> now divide by -2

-2x/-2 = 10/-2

--> on the left, the -2's cancel, leaving only x

x = -5

...or you could have subtracted 2x from both sides:

2x - 2 - 2x = 4x + 8 - 2x

-->

-2 = 2x + 8

--> subtract 8

-2 - 8 = 2x + 8 - 8 --> -10 = 2x

--> divide by 2

-10/2 = 2x/2 --> 2's cancel, again, leaving x = -10/2 = -5 <-- same as what we got the "other" way.

2x - 2 = 4x + 8

2x - 2x - 2 = 4x - 2x + 8

-2 = 2x + 8

-2 - 8 = 2x + 8 - 8

-10 = 2x

-10/2 = 2x/2

-5 = x

You can do either way. It won't change your answer. I would suggest subtracting 2x first, to avoid working with negatives. You can do this first or add 2 first, it doesn't matter. If you wanted you could subtract 4x or subtract 8, but this way is slightly easier.

Just group the similar terms in one side of the equation. When you take a term to the other side of the equality, the sign changes.

-2-8=4x-2x

rearranging.

2x=-10

x=-5