Help with one math question?

50/(2/3) = 150/2 = 75

So basically we have a total of 50 acres, and we need to divide it into 2/3 acres because that is how much each cow needs. So we just do 50 and divide it by 2/3 to see how many times we can fit 2/3 into 50.

Let's consider the situation if each cow would require 1 acre.

Then, we could just divide the whole area of grazing land by the area needed by each cow.

Therefore, it would be just 50 / 1 = 50, hence, 50 cows would fit there.

However, now we have a situation where each cow requires 2/3 of an acre, but it is the same thing!

Therefore,

50 / (2/3) = 50 * (3/2) = 150 / 2 = 75 (or you can use calculator as well)

Think of this:

4 kids, each need 2 dollars. Altogether they need 8 dollars. How did you do that?

4*2 = 8

Now, if the question was missing the number of kids?

x*2 = 8 divide both sides by 2

x=4

Each cow needs 2/3 of an acre.

If you had 3 cows, then 3*(2/3) would be 2 acres needed for them.

2/3*3 = 3 You can see the three different variables in this equation. Which one is missing in your text question?

The number of cows.

2/3* x = 2 divide both sides by 3

x = 2 divided by 2/3 ( we don't divide by fractions, but multiply by the inverse).

x = 2 * 3/2 = 3

In your question, there are 50 acres, not 2

So

2/3x = 50 multiply both sides by the inverse of 2/3

do the rest

enough for 75 cattle.

1 cow = 2/3 an acres

X cows = 50 acres

cross multiply

50= (2/3)x

X=75 cattle

if every cow needs 2/3 of an acre you need to find how many times you can take 2/3 away from 50. This is called division. With a fraction you do it by turning the fraction upside down & multiplying it

ie.

50 x 3 / 2 = 150 / 2 = 75

X cows ~ 50 acres

1 cow ~ 2/3 acre

>=====< (X cows)/(50 acres) = (1 cow)/(2/3 acres)

>=====< X cows = [(50 acres)*(1 cow)]/(2/3 acres)

>=====< X cows = (50)/(2/3) cows

>=====< X cows = (50)*(3/2) cows

>=====< X cows = 75 cows

.'. Matt's land can support 75 cows

1 cow requires 2/3 of 50 acres, i.e 1 cow=100/3 acres, then 50 acress require x cows. I.e (100/3)x=50, 100x=150, x=150/100, x=1.5. Therefore, 50 acres of the land can contain 1.5 cows.

50/(2/3) = (3/2)50 = 75

75

I think answer is (int ) 50/3 * 2