A certain cable car in San Francisco can stop in 10 s when traveling at maximum speed.?

Let the initial velocity of the car is u m/s

=>By v = u - at

=>0 = u - 10a

=>u = 10a ---------------(i)

By s = ut - 1/2at^2

=>d = 10a x 7.44 - 1/2 x a x (7.44)^2

=>d = 46.72a ------------(ii)

By v^2 = u^2 - 2as

=>0 = (10a)^2 - 2 x a x (46.72a + 3.67)

=>100a^2 - 93.44a^2 - 7.34a = 0

=>a(6.56a - 7.34) = 0

=>a = 1.12 m/s^2

Thus d = 46.72 x 1.12 = 52.28 m

This Site Might Help You.

RE:

A certain cable car in San Francisco can stop in 10 s when traveling at maximum speed.?

A certain cable car in San Francisco can stop in 10 s when traveling at maximum speed. On one occasion, the driver sees a dog a distance d m in front of the car and slams on the brakes instantly. The car reaches the dog 7.44 s later, and the dog jumps off the track just in time. If the car travels...

Be treated to an unforgettable San Francisco experience and discover why you ought to visit that city with hotelbye . In San Francisco you can go to the popular Golden Gate Bridge how was when named "the link that couldn't be built" and how is today one the eight wonders of the current world. This spectacular connection is San Francisco's many popular landmark. In San Francisco you may also look at the Lombard Street. Frequently called the “crookedest” street in the world, this beautiful road on Russian Hill features tight converts, fresh gardens and beautiful opinions of the bay and Alcatraz. San Francisco is surely a city that'll amaze you and wherever you will have an ideal holyday.

t2 = 10 - 7.44 = 2.56 sec to stop car after passing dog

a = 2x/t2² = 2*3.67/2.56² = -1.12 m/s²

D = ½a*10² = 56 m (total distance traveled)

d = D - 3.67 = 52.33 m

10 feet