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What are the possible ways to solve 2 unknowns in 3 equations?

How would I solve 2 unknowns in 3 equations? For instance in a Ramsay-Shields equation 3 conditions are given and the unknown are k and tc

***Ramsay Shields equation= (M/P1)^2/3=k(tc-t1-6) 3 conditions are given and we have to solve for the value of k and tc

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  • 8 years ago
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    I have 3 eqns and 2 unknowns Hb and Hbo2, they

    look like this: Bxy = AB * HB + AB * Hbo2 Rxy = AR * HB + AR * Hbo2 Gxy = AG * HB + AG * Hbo2 Now I have been trying to use a matrix method in

    order to solve the unknowns for them equations,

    which is a pain in the *** cause when I convert it to

    matrix form I get an irregular matrix because it is 2

    unknowns and 3 equations. Does anyone on here know how to solve n number

    of equations with n-1 unknowns. EDIT Thanks for the responses so far, they have been

    great. To help make this more clear, what I am trying to

    do is work out the concentration of oxygenated

    and deoxygenated blood at a given pixel in an

    image. so the variables above correspond to the

    following. Rxy Gxy and Bxy, red green or blue absorbed at

    position x,y. (value between 0 - 255) AR, AG, AB is the absorption coefficient of light for

    Red geen and blue wavelengths for blood.

    (HOWEVER there is a possibility I might have to

    define different absorption coefficients for

    oxygenated and deoxygenated blood (as they

    absorb different amounts of light)). Hb and Hbo2 is the concentration of Oxygenated

    and Deoxygenated blood. (these are unknown as

    I'm trying to map the RGB values to this) However I have also noticed that the coefficients for

    Oxygenated and Deoxygenated blood are different

    so this means the equation could possibly be the

    following. Bxy = (ABhb * HB) + (ABhbo2 * Hbo2) Rxy = (ARhb * HB) + (ARhbo2 * Hbo2) Gxy = (AGhb * HB) + (AGhbo2 * Hbo2) The only difference in the above is that the

    coefficients are different for oxygenated and

    deoxygenated blood

    Source(s): google
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