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Calculus problems on limits?
Can someone explain how to find the limit of 7sin(5x) / sin(4x) as x->0 and tan(6z) / sin(3z) as z->0?
1 Answer
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- ZeroLv 48 years ago
Use L'Hopital's Rule.
35cos(5x) / 4cos(4x) as x->0 = 35/4
6sec^2(6z) / 3cos(3z) z->0 = 6/3 = 2
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