Algebra . 11x - 3 = 3x + 37?

11x - 3 = 3x + 37 Now collect like terms- i.e. put the xs on one side and the numbers on the other

8x = 40 Now divide both sides by 8 to see what x is

x = 5

:)

11x - 3 = 3x + 37

11x - 3x = 3 + 37

8x = 40

(1/8)(8x) = (1/8)(40)

x = 5

Prove:

Let x = 5

11(5) - 3 = 3(5) + 37

55 - 3 = 15 + 37

52 = 52

Answer is x = 5

First you need to get all the x's on one side and the numbers on the other

11x - 3x = 37 + 3

This gives 8x = 40

Then divide both sides by 8 to give x = 5

11x - 3 = 3x + 37

11x - 3x = 3 + 37

8x = 40

x = 40/8 = 5

11x - 3x = 37+3

8x=40

x=5 (40 divided by 8)

11x -3=3x + 37

11x - 3x = 37+3

8x=40

x=5

11x - 3 = 3x + 37

11x-3x=37+3

8x=40

x=5//

11x-3+3=3x+37+3

11x-3x=3x-3x+40

8x=40

x=5

I'll help you.

You need to cancel the x and cancel one of the numbers. I recommend you cancel the 11 and the 37. After that you would have to plus 3x+11x and -3-37. After that, you divide the x and the number. Hope this is clear enough.

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