(matlab); arrays are given as x=[ 4 12 -5 2 10], y=[ 8 -6 -19 3 -7] use matlab to compute z= (5+x)/(y^2-xy)?

Question

Question 1)                arrays are given as x=[ 4 12 -5 2 10], y=[ 8 -6 -19 3 -7] use matlab to compute z= (5+x)/(y^2-xy)
a) show the long way to calculate z (you will have 5 lines)
b)use a for loop to calculate z
c) use vectorization to calculate z 

question 2) set up a column vector x, which contains the values 1 thru 5, inclusive. use this variable, and matlab array operators to create new variables containing the values below
a) 2 4 6 8 10
b)1 1/2  1/3  1/4  1/5 (note, matlab will display 0.5000, not 1/2)
c) 1 4 9 16 25 36 49 64 81 100
d) 1/2 1 3/2 2 5/2

Anonymous · Accepted Answer

1a)
x = [4 12 -5 2 10]
y = [8 -6 -19 3 -7] 

z(1) = (5+x(1)) ./ (y(1).^2 - x(1) .* y(1))
z(2) = (5+x(2)) ./ (y(2).^2 - x(2) .* y(2))
etc.

1b)
See this example:
matrixlab-examples.com/iteration.html

1c)
z = (5 + x) ./ (y.^2 - x.*y)


2)
See these examples:
matrixlab-examples.com/vectors.html

Anonymous · Answer

you are able to extract submatrices promptly. no opt for to apply loops. B = A(a million:3,2:5) or % outline rows and columns [r c] [r c] [r c] [r c]= length(A) B = A(a million : r, 2 : c-a million) the area less than provides extra examples

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(matlab); arrays are given as x=[ 4 12 -5 2 10], y=[ 8 -6 -19 3 -7] use matlab to compute z= (5+x)/(y^2-xy)?

2 Answers