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Can someone solve this problem?
Let g(x)=9x^(2)-7
(a) Find the average rate of change from -4 to 2
(b) Find an equation of the secant line containing (-4,g(-4)) and (2,g(2))
2 Answers
- 8 years ago
A)avg rate of change will be the slope of the secant line which will be (g(2)-g(-4))/(2-(-4))
g(-4)= 9*(-4)^2-7
g(-4)=9*16-7
g(-4)=144-7
g(-4)=137
g(2)=9*2^2-7
g(2)=9*4-7
g(2)=36-7
g(2)=29
Average rate of change= (29-137)/(2-(-4))=-108/6=-18
(b) To find the equation is simple use on of the two points you found and the Average rate of change which is the slope of the secant line and using point slope form find an equation..
(2,29) and m=-18
using (y-y1)=m*(x-x1)
y-29=-18*(x-2)
y-29=-18x+36
y=-18x+36+29
y=-18x+65
and this is the equation of the secant line. Hope this helps
Source(s): :D - 8 years ago
I didn't understand (a) so...
(b) g(-4)=9*(-4)^(2)-7 = 137. (-4,137)
g(2)=9*(2)^(2)-7=36. (2,36)
(137-36)/(-4-2)=16.83333333333
y-36=16.83333333(X-2)
y-36=16.83333333X-33.66666666666
y=16.833333333X-2.3333333333
Not sure at all that this is correct but... it's something.
