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4 Answers
- Old Science GuyLv 78 years agoFavorite Answer
it takes one Joule to move 1 Coulomb of charge through a potential difference of one volt
V = J/C
there are 6.24E18 electrons per Coulomb or inverted, 1.60E-19 Coulombs per elctron
and mega means 1E6
Mev is the energy to move one electron through a potential difference of 1E6 volts
so
J = V*C = 1E6 v * 1.60E-19 C/e- = 1.6E-13 J/e-
meaning
1.6E-13 J/Mev
or inverted
6.24E12 Mev/J
- 5 years ago
The drive of attraction between every electron and the nucleus, is exactly equal in magnitude (and reverse in path) to the centrifugal force appearing on every electron. The Bohr mannequin of the atom is a theoretical assemble created by means of analogy with the elliptical orbits of the planets across the solar. For more knowledge, see wikipedia "Bohr atom". This may increasingly provide an explanation for electron vigour stages, etc. Hope this helps.
- OldPilotLv 78 years ago
: Convert electron volts to kg.
http://search.yahoo.com/search?p=electro%E2%80%A6
1 GeV = 1.783 * 10^-27 kg
Giga: 10^9
10^9 eV = 1.783 * 10^-27 kg
1 eV = 1.783 * 10^-36 kg
eV is a unit of Energy and that relates to Mass through E = Mc^2. That is why the conversion involves division by c^2
- Zack MLv 58 years ago
divide by 1.6*10^-19 will give you electron volts, i forget what Mega is 10^9? , just divide by the exponent value of mega (your J/ 1.6*10^-19 answer)