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how to solve precalc problem?
Here's the problem: 3^(x+2)=5^x
how do you solve this??
i got
ln3^(x+2)=ln5^x
(x+2)ln3=xln5
2ln3+xln3=xln5
-xln3 -xln3
ln9=xln5-xln3
ln9=x(ln5-ln3)
ln9=x(ln5+ln(1/3))
ln9=x(ln(5 1/3))
x=ln9/ln(5 1/3)
but I feel like this is wrong..
5 Answers
- icemanLv 78 years agoFavorite Answer
3^(x+2)=5^x
3^x * 3^2 = 5^x
5^x/3^x = 3^2
(5/3)^x = 3^2
x ln(5/3) = ln(3^2)
x = 2ln(3)/[ln(5) - ln(3)]
- 8 years ago
3^(x+2)=5^x
(x+2)ln3=xln5
xln3+2ln3=xln5
x(ln3-ln5)=-2ln3
x=(-2ln3)/(ln5-ln3)
x=-ln9/ln(5/3)
- VFBundyLv 68 years ago
3^(x+2) = 5^x
3^(x+2) = 3^0.682606194x
x + 2 = 0.682606194x
0.317393806x = -2
x = -6.301320206
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- parrieraLv 45 years ago
a million. F(x) = 7x^2 - 5x + x^(a million/2) + 3x^(-5) F'(x) = 14x - 5 + (a million/2)x^(-a million/2) - 15x^(-6) = 14x - 5 + a million/(2sqrt(x)) - 15/(x^6) 2. factors the position tangent line is horizontal is the position the slope, or spinoff, is 0. F'(x)=3x^2 + 6x - 24=0 x = -4, 2 change into the unique function to discover the y values. factors (-4, ninety 2) and (2, -16)
