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Linda
Linda asked in Science & MathematicsMathematics · 8 years ago

how to solve precalc exponential?

problem: xe^x+e^x=0

i'm supposed to factor out a GCF

so i get

e^x(x+1)=0

/(x+1) /(x+1)

e^x=0

x=ln0

no solution

i think this is wrong..

3 Answers

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  • daSVgrouch
    Lv 7
    8 years ago
    Favorite Answer

    your factoring is correct

    e^x(x+1) = 0

    one way to get zero is x = -1

    e^x is never 0, but it could be really small as x -> negative infinity

  • Mike G
    Lv 7
    8 years ago

    e^x(x+1)=0

    e^x = 0 >>>no solution

    (x+1) = 0

    x = -1

  • L
    8 years ago

    e^x = 0 or x+1=0

    The first condition has no solution, but the second has one.

    x=-1

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