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help with an algebraic math question?
i cant figure out these two word problems.
1) seperate the number 24 into two parts so that one number is twice the other number.
2) sperate the number 38 into two parts so that one number is 6 less than the other number.
2 Answers
- ?Lv 58 years agoFavorite Answer
24 = 2x + x
24 = 3x
24 / 3 = x
8 = x
Therefore,
first number = 8, second number = 16
2) 38 = x - 6 + x
38 = 2x - 6
32 = 2x
32 / 2 = x
16 = x
So, 16 = first number; second number = 22
- ?Lv 58 years ago
1) Whenever a word problem says "one number is twice the other number and they add up to __" always divide by 3! So 24 /3 = 8. Then add two of the 8's together to get 16. 16 is twice as much as 8 and they add up to 24!
Answer: 8 and 16
2) First divide 38 by 2 to get 19. Then subtract 6 from one of the 19s to get 13 and add it to the other 19 to get 25.
Answer: 13 and 25