Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Help Me Understand Hyperbola Question?
I need to find the center and vertices of the conic section.
4y^2 - x^2 - 4x - 8y - 4 = 0
From there I would group my X and Y terms and move the -4 to the other side.
(4y^2 - 8y) - (x^2 - 4x) = 4
The next part is where I get confused when I take the 4 out of the 4y^2 as a common factor.
4(y^2 - 2y ) - (x^2 - 4x ) = 4
In the next step, it shows me inputting a 1 with my y-terms and a 4 with my x-terms, this is the part that always confuses me. Can anyone explain how I properly get to the 1 and the 4 in those empty spots?
1 Answer
- ?Lv 78 years agoFavorite Answer
try doing this way:
4y^2 - x^2 - 4x - 8y - 4 = 0
(4y^2 - 8y) - (x^2 + 4x) = 4 => you have some mistake here
4(y^2 - 2y ) - (x^2 + 4x ) = 4
4[(y-1)^2 - 1^2] - [(x+2)^2 - 2^2] = 4
4(y-1)^2 - 4 - (x+2)^2 +4 = 4
4(y-1)^2 - (x+2)^2 = 4
(y-1)^2 / 1 - (x+2)^2 / 4 = 1