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How do you solve for x in this: 12x=32+x^2?
4 Answers
- navinLv 78 years agoFavorite Answer
12x = 32 + x^2
=> x^2 - 12x + 32 = 0
=> x^2 - 8x - 4x + 32 = 0
=> x(x - 8) - 4(x - 8) = 0
=> (x - 8)(x - 4) = 0
=> x - 8 = 0 or x - 4 = 0
=> x = 8 or x = 4 Ans.
- Bob BLv 78 years ago
Subtract 12x from both sides:
0 = x^2 - 12x + 32
Factor to:
0 = (x - 4)(x - 8)
Solutions are x = 4 and x = 8
- 8 years ago
first bring 12x to the other side
so it would be
0=x^2-12x+32
then use the quadratic formula
- 8 years ago
move 12x to the other side and equal it all to zero. Hope I helped. Xx. Your answer should be ---> (x-8)(x-4)