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The mole fraction of potassium bromide in the solution is ???.?
An aqueous solution is 3.50 % by mass potassium bromide, KBr, and has a density of 1.02 g/mL.
1 Answer
- Lexi RLv 78 years agoFavorite Answer
3.50 % by mass KBr means that 3.50 % of the total mass of the solution is KBr
So in 100 g of the solution you have
3.50 g KBr and
96.5 g H2O
mole fraction KBr = moles solute / total moles in solution
moles KBr = mass / molar mass = 3.50 g / 119.002 g/mol = 0.029411 mol
moles H2O = 96.5 g / 18.016 g/mol = 5.35635 mol
total moles in the solution = 0.029411 mol + 5.35635 mol = 5.38576 mol
mole fraction KBr = 0.029411 mol / 5.38576 mol
= 0.00546
