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emorella
emorella asked in Science & MathematicsEngineering · 8 years ago

circuit question 2 please help thanks :)?

A 16-ohm resistor is connected in series with a parallel combination of 2 resistors, one of which has an ohmic value of 48 ohms, the other one R , being unknown. What is R if the power taken by the 16-ohm unit is equal to the power in the parallel-connected pair of resistors?

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  • ?
    Lv 7
    8 years ago
    Favorite Answer

    The two parallel resistors must equal 16Ω for their power dissipation to equal the 16Ω resistor.

    16Ω = R(48Ω)/(R + 48Ω)

    16R + 768 = 48R

    32R = 768

    R = 24Ω

  • Mr. Un-couth
    Lv 7
    8 years ago

    R =16 Ohms / (1 - 16/48) = 24 Ohms

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