help with this algebra fraction equation?

2/5*(5*x-3)-1/3*(12*x-5)

2/5 = 0.4

1/3 = 0.34

0.4*(5*x-3)-0.34*(12*x-5)

2x-1.2-4.08x+1.7

Put them in order:

2x - 4.08x +1.7 -1.2

-2.08+0.5

= 0.5 - 2.08

= -1.58

2/5*(5*x-3)-1/3*(12*x-5)

This more clearly written as

2(5x - 3) / 5 - (12x - 5) / 3

Bring to a common denominator (bottom number ) of 15 ( = 5 x 3)

Then the left hand terms is multiplied by '3' and the right hand term by '5'

Hence

[2(3)( 5x - 3) - 5(12x - 5) ] / 15

Multiply out the brackets

[30x - 18 - 60x + 15] / 15

Collect 'like' terms in the 'square' brackets

[-30x - 3] / 15

Divide through by '15'

-30x/15 - 3/15

Cancel down

-2x - 1/5

-2x - 0.2 ( in decimal form).

So neither simplification is 'True'.

on the grounds that this is a situation the position fractions are being further mutually, you first ought to locate an trouble-free denominator. the easy denominator of four and x might want to be 4x because thats the in trouble-free terms trouble-free dissimilar of both. once you modify the denominator of one million/4 to 4x you're multiplying the denominator by technique of x so that you may do this to the numerator besides. a million circumstances x equals x. so the first fraction is changed to x/4x. to modify the denominator of one million/x to 4x you multiply the denominator by technique of four so that you may also do this to the numerator. a million circumstances 4 is for thus the 2d fraction is 4/4x so your equation is now x/4x + 4/4x purely upload the numerators mutually the purely top answer is (x+4)/4x