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Help solving a log problem 10 points?

log (base b) x - log (base b) 5 = log (base b) 2 - log (base b) (x-3)

Thank you!

3 Answers

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  • None
    Lv 7
    8 years ago
    Favorite Answer

    since all the logs are to the same base,

    log (b) x - log (b) 5 = log (b) 2 - log (b) (x-3)

    x/5 = 2/(x - 3)

    x^2 - 3x = 10

    x^2 - 3x - 10 = 0

    (x - 5)(x + 2) = 0

    x = 5, -2

  • 8 years ago

    Well, since the logs are subtracting, you set them up to divide.

    log(base b) x/5 =log (base b) 2/x-3

    Since the logs have the same base, you can cancel them out which leaves you with

    x/5=2/x-3

    You then "cross multiply" and get x^2-3x=10

    Move the 10 over and set it equal to 0.

    Then factor (x-5)(x+2)

    And so on. The answer can't make log negative.

    Source(s): AP PreCalc
  • 8 years ago

    logx-log5=log(x/5) and log2-log(x-3)=log(2/(x-3))

    so x/5=2/(x-3) this implies x^2-3x-10=0 -> (x-5)(x+2)=0 implies x=5 or x=-2

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