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Help solving a log problem 10 points?
log (base b) x - log (base b) 5 = log (base b) 2 - log (base b) (x-3)
Thank you!
3 Answers
- NoneLv 78 years agoFavorite Answer
since all the logs are to the same base,
log (b) x - log (b) 5 = log (b) 2 - log (b) (x-3)
x/5 = 2/(x - 3)
x^2 - 3x = 10
x^2 - 3x - 10 = 0
(x - 5)(x + 2) = 0
x = 5, -2
- 8 years ago
Well, since the logs are subtracting, you set them up to divide.
log(base b) x/5 =log (base b) 2/x-3
Since the logs have the same base, you can cancel them out which leaves you with
x/5=2/x-3
You then "cross multiply" and get x^2-3x=10
Move the 10 over and set it equal to 0.
Then factor (x-5)(x+2)
And so on. The answer can't make log negative.
Source(s): AP PreCalc - 8 years ago
logx-log5=log(x/5) and log2-log(x-3)=log(2/(x-3))
so x/5=2/(x-3) this implies x^2-3x-10=0 -> (x-5)(x+2)=0 implies x=5 or x=-2