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Lv 6
Integrate the equation...?
d(v^2/2) + dp/(rho) = 0 for an isentropic process where p / (rho)^gamma = constant.
Explain the result.
Please help
1 Answer
Relevance
- GusBsAsLv 68 years agoFavorite Answer
p = C rho^gamma
dp = C gamma rho^(gamma-1) drho
dp / rho = C gamma rho^(gamma-2) drho =
= d(C gamma/(gamma-1) rho^(gamma-1)) =
= d (gamma/(gamma-1) p/rho)
=>
d (v^2/2 + gamma/(gamma-1) p/rho) = 0
=>
v^2/2 + gamma/(gamma-1) p/rho = constant
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