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Chemisty help please! Acids an base equations?
Help please! How do I find the answers???
1)What is the pKb valve for F-?
Table listed:
acid=HF Ka =6.8x10-^4 base=F- Kb=1.5x10^-11
Please help!
2) Table :
Given that Ka for HCN is 4.9x10^-10 and Kb for NH3 is 1.8x10^-5 caluclate Kb for CN- and Ka for NH4+
Enter the value Kb value for CN - followed by the Kb value for NH4+ , separated by a comma, using two significant figures?
2 Answers
- HPVLv 78 years agoFavorite Answer
1) pKb = -log Kb = -log (1.5 x 10^-11) = 10.82
2) Kb CN- = Kw / Ka HCN = (1.0 x 10^-14) / (4.9 x 10^-10) = 2.0 x 10^-5
Ka NH4+ = Kw / Kb NH3 = (1.0 x 10^-14) / (1.8 x 10^-5) = 5.6 x 10^-10
- 4 years ago
a million. dissociation of NaOH: NaOH(s) + H2O ------------> Na+(aq) + OH-(aq) 2. Ionization of HCl: HCl(g) + H2O ---------> H3O+(aq) + Cl-(aq) NaOH dissociaes because of the fact it fairly is already ions interior the organic state: water helps the ions to chop up. HCl ionizes because of the fact interior the organic state it fairly is molecular and water pulls it aside into ions. It does not dissociate interior an identical experience NaOH does. HCl(aq) + NaOH(aaq) -----------> NaCl(aq) + H2O(l)
