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Mako
Lv 7
Finding the sum of series?
(x-5)^n from n=1 to infinity.
I am supposed to do 1/(1-r) ? the answer isn't 1/(1-(x-r)) so what would it be? I'm so confused.
1 Answer
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- 8 years agoFavorite Answer
Sum from n=0 to n= infinity of X^n=1/(1-X) for|X|<1 ie -1<X<1
So your function only makes sense as a sum of series if X=(x-5) and |x-5|<1.
ie -1<x-5<1 Adding 5 to all values:
=>4<x<6
Answer:
Sum = 1/(1-(x-5))
=1/(6-x), for 4<x<6.
Hope this helps.
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