Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Kirchoff's law problem?
How can I find the current in each of the branch of the circuit?? I'm just a bit confused thanks :)) Here's the circuit link http://img832.imageshack.us/img832/4049/2013031719... (sorry for the wrong orientation -_-)
1 Answer
- Anonymous8 years agoFavorite Answer
Assume currents I1 to I7 through the resistors labeled from top to bottom and left to right.
Assume the current through I1 is left to right.
Assume the current through I2 is right to left
Assume the current through I3 is up to down.
Assume the current through I4 is right to left.
Assume the current through I5 is left to right.
Assume the current through I6 is right to left.
Assume the current through I7 is right to left.
These assumptions mean the currents are flowing out of the + terminals of the three batteries.
Kirchhoff's Current Law for:
top node: I1 + I2 = I3
middle left node: I4 + I6 = I1
middle center node: I3 = I4 + I5
middle right node: I5 = I2 + I7
Kirchhoff's Voltage Law for:
top left loop going clockwise: -14 + 7(I1) +5(I3) + 4(I4) = 0
top right loop going counterclockwise: - 32 + 6(I2) + 5(I3) + I5 = 0
bottom loop going clockwise: - 20 + 8(I6) - 4(I4) + I5 + 4(I7) = 0
Solving these simultaneously you get: I1 = +0.41 A; I2 = +2.40 A; I3 = +2.81 A
I4 = - 0.72 A; I5 = +3.53 A; I6 = +1.13 A I7 = +1.13 A
So all directions were assumed correctly except I4 because it got a negative result. So the current for I4 will be left to right.