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How do I find margin of error percent given distance?
I don't think my question was very clear, but basically, I am trying to find n, given:
n = p(1-p)((z_alpha/2)/E)^2
However, up until now, I have been given E or margin of error as a percent. It's now represented by a number of millimeters. How do I find the percent to plug into the above formula? Would it be E/mean or E/Standard Deviation?
1 Answer
- GuyLv 78 years agoFavorite Answer
The formula you gave is for proportions. There is a similar one to use with means:
n = (z_a/2 * sigma / E)^2
