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i need math help please!?

how do i calculate the answer to this?

log base2 of 8^99

5 Answers

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  • ?
    Lv 7
    8 years ago
    Favorite Answer

    8^99 = (2^3)^99 = 2^297

    Answer 297

  • ?
    Lv 7
    8 years ago

    log base2 of 8^99

    = log base2 of (2^3)^99

    = log base2 of 2^(3*99)

    = log base2 of 2^297

    = 297log base2 of 2

    = 297 * 1

    = 297 Ans.

  • 8 years ago

    log2(8^99)

    You can pull exponents out of logs:

    99 * log2(8)

    The log2(8) = 3 because 2^3 = 8, so:

    99 * 3 =

    297

    Source(s): BA in Mathematics
  • 8 years ago

    There are 2 basses on a log so multiplyu it by 2 and add it to 8^99th power

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  • Anonymous
    8 years ago

    Not sure but i think it 2x2x2=8 so u need to multiply 3 of the. 2to get 8 so the logarithm is 3.

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