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i need math help please!?
how do i calculate the answer to this?
log base2 of 8^99
5 Answers
- ?Lv 78 years ago
log base2 of 8^99
= log base2 of (2^3)^99
= log base2 of 2^(3*99)
= log base2 of 2^297
= 297log base2 of 2
= 297 * 1
= 297 Ans.
- RU MattLv 68 years ago
log2(8^99)
You can pull exponents out of logs:
99 * log2(8)
The log2(8) = 3 because 2^3 = 8, so:
99 * 3 =
297
Source(s): BA in Mathematics - How do you think about the answers? You can sign in to vote the answer.
- Anonymous8 years ago
Not sure but i think it 2x2x2=8 so u need to multiply 3 of the. 2to get 8 so the logarithm is 3.