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Lv 7
? asked in Science & MathematicsMathematics · 8 years ago

The find the order of degree of the differential equation(d^3y/dx^3)^4/5 - 2*dy/dx(d^2y/dx^2)^2 = 0?

Please explain.

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  • Learner
    Lv 7
    8 years ago
    Favorite Answer

    i) I suppose it must be order & degree of the differential equation ....

    and not as order of degree of the differential equation ....

    ii) Rearranging the given one it is: (d³y/dx³)^(4/5) = 2*(dy/dx)(d²y/dx²)²

    iii) Taking 5th power of the above on both sides,

    (d³y/dx³)⁴ = 32*(dy/dx)⁵(d²y/dx²)¹°

    Thus the given one is: (d³y/dx³)⁴ - 32*(dy/dx)⁵(d²y/dx²)¹° = 0

    Its highest order is 3, whose degree is 4

    So the order & degree of the given differential equation is: 3 & 4

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