Is this function one to one...Please Help?

The graph of that function is just a line with a slope of 5, so it is one-to-one and its domain and range are all real numbers. To find the inverse, interchange x and y:

f(x) = 5x - 6

y = 5x - 6

x = 5y - 6

5y = x + 6

y = (1/5)x + 6/5

So, the inverse is f^-1(x) = (1/5)x + 6/5

Hope that helps :)

yes, it is one to one. (for every input value, there is only one output value and vice-versa)

Its inverse is determined by swapping the variables in the function. Instead of f(x) = 5x-6, the new function would be x=5y-6. Solve for y and you get y=(x+6)/5

The domain is all real numbers. For every possible real number entered in as x, the output value, y, is equal to a real number

The range is also all real numbers.