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- ?Lv 68 years ago
I think the last h should be under everything, not hust the final f(x)
[f(x + h) - f(x)] / h
[3(x+h)^2 + 3x^2] / h
[3(x^2 + 2xh + h^2) - 3x^2] / h
[3x^2 + 6xh + h^2 - 3x^2] / h
h(6x+h) / h
6x+h
Next step, take the limit as h approaches zero
6x
- Anonymous8 years ago
f(x+h)=3(x+h)^2,f(x)=3x^2.
So, [f(x+h)-f(x)]/h=[3(x+h)^2-3x^2]/h=3(h^2+2xh)/h=
3h+6x. Ans.
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