Write the point slope form of the line, satisfying the given conditions?

(2,6) (5,15)

15 - 6. 9

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5 - 2. 3

9/3 = 3/1 or 3

Now, substitute:

y=mx+b

y = 6

x = 2

m = 3

6=3(2)+b

6=6+b

b = 1

Final Equation:

y=3x+1

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(:

y = mx + b m = slope b = y-intercept a million. y = (a million/2)x + b 4 = (a million/2)6 + b 4 = 3 + b a million = b y = (a million/2)x + a million 2. initiating = (0, 0) y = 5x + b 0 = 5(0) + b 0 = 0 + b 0 = b y = 5x 3. m = (a million - 7) / (6 - 6) = -6 / 0 = undefined slope undefined slope potential vertical line and the equation for a vertical line is x=?, in view that the two factors use 6 via actuality the x, it is the equation: x = 6

Y =3x. Which means a slope of 3 and y intercept of 0 calculated in my head BTW so not sure if correct

m = (15 - 6) / (5 - 2)

m = 9 / 3

m = 3

y - y1 = m(x - x1)

y - 15 = 3(x - 5)

or

y - 6 = 3(x - 2)