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using the given conditions to write an equation for the line in point slope form and general form......?
Passing through(-9,1) and and parallel to the line whose equation is 3x-5y-9=0
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- DavidLv 78 years agoFavorite Answer
3x - 5y - 9 = 0
-5y = -3x + 9
y = (3/5)x + 9/5
slope is 3/5
parallel lines have equal slopes
y - 1 = (3/5)(x - (-9))
y - 1 = (3/5)(x + 9) [point slope form]
y - 1 = (3/5)x + 27/5
y = (3/5)x + 32/5 [slope intercept form]
5y = 3x + 32
-3x + 5y = 32
3x - 5y = -32 [standard form]
3x - 5y + 32 = 0 [general form]
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