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Find a polar equation for the curve represented by the given Cartesian equation?
Find a polar equation for the curve represented by the given Cartesian equation
4y^2 = x
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- Robert CottonLv 58 years agoFavorite Answer
i use t for theta
y=rcos(t)
x=rsin(t)
put those in when you changing from cartesian to polar
4[rcos(t)]^2=rsin(t)
4r^2[cos(t)]^2=rsin(t)
4r[cos(t)]^2=sin(t)
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