Theoritically, how loud would a sound over 9000 dB be?

You want to listen to sound? We measure the sound with an SPL meter. SPL = Sound Pressure Level. Our eardrums are moved by the sound pressure deviations.

Reference sound pressure po = 20 µPa = 2×10^−5 Pa (Threshold of hearing).

Reference sound pressure level Lpo = 0 dB-SPL (Threshold of hearing level).

Get sound pressure p in Pa when entering sound pressure level Lp = 9000 dB.

Sound pressure p = po×10^(Lp/20) Pa (= N/m²) = 2×10^−5×10^(9000/20) Pa =

Sound pressure p = 2.0×10^445 Pa.

Threshold of pain is at 150 Pa, that is 137.5 Pa.

More level will slash at least your aerdrums.

The chaos in the center of an explosion of an atom bomb will show more than 200 dB sound level.

In theory we can imagine a level of 9000 dB when two stars bang together in the universe.

But because there is vacuum - there is no medium like air - we will hear really no sound!

There will be a very big pressure wave.

Cheers ebs

120 dB is very painful. 9000 db is 8880 dB higher

every 10 dB is a factor of 10, so this is 10^888 higher, an impossibly large number, 1 followed by 888 zeros.

reference lists 194 dB as the theoretical limit for undistorted sound at 1 atmosphere environmental pressure.

If you just want pressure limits, see second link. Max pressure listed that makes sense is that inside a nuclear warhead explosion (which you could never hear) which is 10^15 Pa. Sinc dB in sound is referenced to 20 µPa, that is about 10^20 larger, but still a far cry from 10^888.

Sounds like the Big Bang...

Yeah, it would probably blow the earth's atmosphere off into space.